What's the definition of acceleration?

The displacement x x of a particle along the x x -axis is given by x = 73 + 65 t 2 10 t x=73+65t^2-10t where t t is the time parameter. What is the acceleration of the particle?


The answer is 130.

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2 solutions

Abishek Nathan
Apr 1, 2015

To find accleration, differentiate the equation of displacement two times

Acceleration = d/dt * dx/dt

d/dt (65t^2 - 10t + 73) = 130t - 10

d/dt (130t - 10) = 130

It's not d/dt

Edit :

d x d t = v \frac{dx}{dt}=v and d v d t = a \frac{dv}{dt} = a

Vaibhav Prasad - 6 years, 2 months ago

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d^2x/(dt)^2 means the same thing :)

Hrishik Mukherjee - 6 years, 2 months ago

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did you try this

Vaibhav Prasad - 6 years, 2 months ago

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@Vaibhav Prasad IDK how to solve diophantine equations.. Saved for solving later :(

Hrishik Mukherjee - 6 years, 2 months ago

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