Super Finn To The Rescue

To put things in order, let's first get the time when the package reaches the ground. Here, we will be using the four kinematic equations, and among those four, the formula, $d=initial velocity\times time + \frac{gt^2}{2}$ (where g is the acceleration due to gravity) I think, is the appropriate one to use. By plugging the given in, we get: $3100 m=(0)\times(t) + \frac{(9.8 m/s^2)\times(t^2)}{2}$ which implies that $t^2=\frac{3100 m}{4.9 m/s^2}$ $t=\sqrt{\frac{3100 m}{4.9 m/s^2}}$ $t=25.15 s$ Now, the question is, "At what distance (horizontally) from the point of release does the package strike the ground?" To answer this, $25.15 s\times 90 m/s=\boxed{2262.2 m} (approximately)$

Simple! since the plane is moving with a uniform velocity, the plane will be exactly above the point where the package strikes the ground. so the horizontal distance covered from the point of release is

x = Velocity * time = 90 * time

Time taken by the plane to fly with uniform velocity is equal to time taken by package to reach ground. so time can be calculated by

s = u.t + 0.5 a. t^2 3100 = 0+ 0.5 * 9.81 * t^2 t =~ 25 s

distance x = 90*25 = 2250

just Use , R = u*(underroot2h/g)

Great problem. It took me a bit of time to figure out what it was asking though. To figure this out, one must know the exact acceleration of gravity 9.81m/s, and the free fall equation.(distance=1/2acceleration X time*2. To figure out the horizontal distance Finn's dropped package travels one must know how long it takes to hit the ground because horizontal and vertical velocity are independent of each other. To do this, simply do the free fall equation using the acceleration of gravity and it should come out to 25.14 seconds, then multiply that by 90 ( the rate ) and get 2262.6 which is about 2260 meters. Mardokay, nice One Piece account picture!