Find the smallest positive integer x such that 4 x + 4 5 5 5 + 4 6 6 6 is a positive integer.
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In fact:
4 4 4 3 + 4 5 5 5 + 4 6 6 6 = 2 4 4 3 1 + 4 1 1 2 + 4 2 2 3
1 + 4 1 1 2 + 4 2 2 3 = 1 + 2 2 2 4 + 4 2 2 3 = 1 + 2 × 2 2 2 3 + ( 2 2 ) 2 2 3 = 1 + 2 2 2 3
So, the expression equals 2 4 4 3 + 2 6 6 6 at x = 4 4 3 which means the answer x would satisfy x ≤ 4 4 3 .
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By the way, with wolframalpha, I found that:
4 6 6 6 + 4 5 5 5 − ( 2 6 6 6 + 2 4 4 3 − 2 2 1 9 + 2 − 4 ) ≈ − 5 . 7 9 5 6 × 1 0 − 6 9
New edit:
Also, by wolframalpha help, I found that 3 3 4 ≤ x ≤ 4 4 3
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How can you know it is 443 if you don't have calculator or wolframalpha?
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@Porames Vattanaprasan – I just stated x<=443, it could be lower but if you ask how 443 work, see above. I posted one solution.
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@Gian Sanjaya – Good luck my friend :)
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We want 4 x + 4 5 5 5 + 4 6 6 6 to take on a perfect square form, so we opt to rewrite it as 2 2 x + 2 ∗ 2 1 1 0 9 + 2 1 3 3 2 . If we try a factorization of ( 2 x + 2 6 6 6 ) ( 2 x + 2 6 6 6 ) , then x = 4 4 3 .