Telescoping Series 7 – Extension

Algebra Level 2

For what value of n n do we get

1 1 × 2 + 1 2 × 3 + 1 3 × 4 + + 1 n × ( n + 1 ) = 0.998 ? \frac{1}{1\times 2} + \frac{1}{2\times3} + \frac{1}{3\times4} + \dots + \frac{1}{n\times(n+1)} = 0.998?

Note: ensure that you can read the entire equation, up to the 0.998 at the end.


The answer is 499.

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8 solutions

Corner Brian
Apr 10, 2014

We have 1/1 - 1/n+1 = 0.998

=> 1/n+1 = 0.002

=> n+1 = 500

=> n = 499

Maham Zaidi
Apr 10, 2014

Just like I explained in the previous problem, the decimals are simply the fraction formed from the denominators. 0.998 is calculated from dividing 499 by 500. n= 499 as 500 is (499 + 1) OR (n+1)

The question doesn't show up in my phone properly. No wonder I don't get it

Frederick Setjadiningrat - 7 years, 2 months ago

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Frederick, can you explain what the issue is? Please email me (Calvin@Brilliant.org) a screenshot, so that I can troubleshoot it. Thanks!

Calvin Lin Staff - 7 years, 2 months ago

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The question doesn't show properly, I got it wrong for that

Ashtik Mahapatra - 7 years, 2 months ago

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@Ashtik Mahapatra Thank you. We will work on ensuring that the entire equation displays properly.

Calvin Lin Staff - 7 years, 2 months ago

hi good

Millat Afghan - 7 years, 1 month ago
Tasnim Rawat
Apr 10, 2014

1 - 1 /1+n = 0.998

n / n +1 =998 /1000

1000 n = 998 n + 998

2n = 998

n= 499

n/(n+1)=0.998 =>n=0.998n+0.998 =>0.002n=0.998 =>2n=998 =>n=499

Keshav Ramesh
Jan 31, 2017

There is a simple way to solve this:

First, convert 0.998 into a fraction - which is 499/500. Since the sum of the terms up to 1/n*(n+1) has to be n/n+1, the value of n=499.

1 1 n + 1 = 499 500 1 - \frac{1}{n+1} = \frac{499}{500}

1 n + 1 = 1 500 \frac{1}{n+1} = \frac{1}{500}

n + 1 = 500 n+1 = 500

n = 499 \boxed{n = 499}

Manu Attri
May 16, 2014

Nice problem

Deepak Gupta
May 2, 2014

separate each term, like 1/1*2=1-1/2 and so on we see that all terms except first and last cancel out and we are left with 1-1/(n+1)=0.998, now solve and get. n=499

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