n do we get
For what value of1 × 2 1 + 2 × 3 1 + 3 × 4 1 + ⋯ + n × ( n + 1 ) 1 = 0 . 9 9 8 ?
Note: ensure that you can read the entire equation, up to the 0.998 at the end.
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Just like I explained in the previous problem, the decimals are simply the fraction formed from the denominators. 0.998 is calculated from dividing 499 by 500. n= 499 as 500 is (499 + 1) OR (n+1)
The question doesn't show up in my phone properly. No wonder I don't get it
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Frederick, can you explain what the issue is? Please email me (Calvin@Brilliant.org) a screenshot, so that I can troubleshoot it. Thanks!
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The question doesn't show properly, I got it wrong for that
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@Ashtik Mahapatra – Thank you. We will work on ensuring that the entire equation displays properly.
hi good
1 - 1 /1+n = 0.998
n / n +1 =998 /1000
1000 n = 998 n + 998
2n = 998
n= 499
n/(n+1)=0.998 =>n=0.998n+0.998 =>0.002n=0.998 =>2n=998 =>n=499
There is a simple way to solve this:
First, convert 0.998 into a fraction - which is 499/500. Since the sum of the terms up to 1/n*(n+1) has to be n/n+1, the value of n=499.
1 − n + 1 1 = 5 0 0 4 9 9
n + 1 1 = 5 0 0 1
n + 1 = 5 0 0
n = 4 9 9
separate each term, like 1/1*2=1-1/2 and so on we see that all terms except first and last cancel out and we are left with 1-1/(n+1)=0.998, now solve and get. n=499
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We have 1/1 - 1/n+1 = 0.998
=> 1/n+1 = 0.002
=> n+1 = 500
=> n = 499