A square is divided into three congruent rectangles. The perimeter of one rectangle is 400 units. What is the perimeter of the square?
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In the second line of your equation, I think you meant 2 ( 3 x ) + 2 x = 4 0 0 ?
At least one of the three rectangles must share a side with the square. Therefore, since they are congruent, they must all be side by side or on top of each other (since each must have one side length equal to the square). This implies that for each rectangle one side must be 1/3 of the length of the other one. Call this side x. Then x + x + 3 x + 3 x = 4 0 0 . So, x = 5 0 and the length of the other side = 3 x = 1 5 0 .
So, each rectangle must be 1 5 0 by 5 0 . 1 5 0 corresponds to one side of the square, so the perimeter of the square is 1 5 0 ⋅ 4 = 6 0 0
Each rectangle must be 1 5 0 by 5 0 .
How do you know that this is true? Why can't there be any other configurations?
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At least one of the three rectangles must share a side with the square. Therefore, since they are congruent, they must all be side by side or on top of each other (since each must have one side length equal to the square). This implies that for each rectangle one side must be 1/3 of the length of the other one. Call this side x. Then x + x + 3x + 3x = 400. So, x = 50 and the length of the other side = 3x = 150.
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@Geoff Pilling Could you incorporate this comment in your answer?
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@Jason Dyer – Done. .............
I guess you bring up an important point. When Pranshu says "equal rectangles" does he mean equal area or the same dimensions?
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That caused me to think about different arrangements where the perimeter is constant but the rectangles are not congruent, and I created this related problem .
@Pranshu Gaba , wanna answer this question? I think the answer is yes
By "equal rectangles", I meant congruent rectangles, that is, rectangles having the same dimensions. Let me edit the problem statement to make it clear.
Let each side of the square be 3x.
Since each square is divided into 3 congruent rectangles, their dimensions will be 3x * x
The perimeter of a rectangle = 3x + 3x + x + x = 8x = 400 (given)
hence x = 5 0
Perimeter of square = 4 ( 3x) = 12x = 6 0 0
Suppose that the square side is a , so the perimeter of the rectangle equals 2 ( a + a / 3 ) = 4 0 0 . Then ( 8 / 3 ) a = 4 0 0 , so a = 1 5 0 . Then the square perimeter equals 4 a = 4 ( 1 5 0 ) = 6 0 0 .
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4 0 0 = 8 x
x = 8 4 0 0 = 5 0
p e r i m e t e r o f t h e s q u a r e = 4 ( 3 x ) = 1 2 x = 1 2 ( 5 0 ) = 6 0 0
Consider the given statements. All the rectangles are congruent, so one side of the rectangle has to be a side of the square (imagine two identical cuts of the square parallel to one side of the square to get the three rectangles). Then we have that the perimeter is 400, so the sum of the two side lengths of a given rectangle is 200. Furthermore, the short side of the rectangle must be 3 times longer than the long side since we have 3 congruent rectangles. Thus we have a system
y = 3x x + y = 200
Substitute and find that x = 50. Trivially, the square side length must be longer than the short side of the square, so the square side length is 200 - x = 150. Then 4x = perimeter of square = 600.
The side of rectangle has 1:3 as their proportion. Because of the perimeter, the sum of its side is 200. So, the longer side of rectangle which is side of square is 200.3/4=150. So, the perimeter of square is 4.150=600
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let y be the length of the rectangle and x be the width of the rectangle
we know that y is also the length of the square and y = 3x
2y + 2x = 400
2y + 2(3x) = 400
x = 50
y = 3(50) = 150
P = 4y = 4(150) = 600