When full, a barrel of water contains 85 litres. How many litres remain after 40% has been used?
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Using mental math:
40% used means that 60% remains. 6 0 / 1 0 0 × 8 5 = 0 . 6 × 8 5 = 6 × 8 . 5 = 6 × 8 + 6 × 0 . 5 = 4 8 + 3
It would have been better if u had interchanged '85' and '60' . :)
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ok man ! done !thanks !
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@Kalash Verma how did you solve this
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@Vaibhav Prasad – Similarly as Solution is given
Why do so many people think useful to add yet another explanation for a substraction followed by a multiplication (or vice-versa)?
It is simple.
60% of tank would be there.
100%=85, 40%=×, When you cross multiply, 100x =40 × 85, x = (40 × 85)/100, x = 34, x is the amount used. To find the amount left, subtract 34 from 85. Therefore, the answer is 51.
100% - 40% = 60% used 60% x 85 = 51
water used = 40/100 * 85 = 34 liters water remained = 85 - 34 = 51 liters so simple ....
(100-40)% of 85 L = 0.6 X 85 L = 51 L
Maybe not elegant, but quick mental math: 85 x 0.10= 8.5 8.5 x 2= 17 17 x 2= 34 85 - 34= 51
Basically, found 10% of 85, multiplied by 4 (well, 2 and then 2 again) to get 40% and subtracted the result from 85.
85 - (85)(40/100) = 85 - (3/5)85 = 85 - 34 = 51
The solution given are correct but let me give a detailed one. Given that 40 litres out of 100 litres are used therefore 60 litres are left.
Similary if 60 litres out of 100 litres are left therefore out of 85 litres 1 0 0 6 0 × 8 5 = 5 1
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40×85÷100=34