The radius of a cylindrical gold coin is and thickness is . How much gold will be required to prepare such coins?
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A coin is cylindrical
Hence, V o l u m e O f A C y l i n d e r = π × R a d i u s 2 × H e i g h t
Radius = 0.7cm i.e. 7 mm Height = 2 mm
V o l u m e O f C o i n = 7 2 2 × 7 × 7 × 2 = 3 0 8 m m 3
Hence Volume Of 10 Coins = 3 0 8 × 1 0 = 3 0 8 0 m m 3