What operations?

Logic Level 4

Using the numbers 1, 3, 4, 6 you need to make the number 24.

You can only use addition, subtraction, division and multiplication, and you can use them any number of times.

The answer should be submitted in the format below: If you used 1 addition, 1 subtraction, 1 division and 1 multiplication your answer should be 1111, If you used 2 additions, 1 subtraction, 1 division and 2 multiplications your answer should be 2112,

1 3 4 6 should be used at least once and not more that once


The answer is 120.

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3 solutions

The answer is 6/(1-3/4). This doesn't need any explanation. 2 divisions and 1 subtraction is used, hence the answer is 0120

Moderator note:

Nice!

Bonus question : If I replace the number 24 by 23 instead, prove that there exist at least 3 solutions.

I also could have 1 × ( 6 3 ) + 4 = 24 1 \times \dbinom{6}{3} + 4 = 24 , then the answer is 1001.

Pi Han Goh - 6 years ago

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but u can only use the 4 basic operators

Ashwath Srikanthan - 6 years ago

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But they they just brackets!! haha, just kidding, nice question! Can you make some more? I enjoyed these questions

Pi Han Goh - 6 years ago

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@Pi Han Goh sure ill make more, and be sure to follow me

Ashwath Srikanthan - 6 years ago

Hi Challenge Master,

I have 1 solution:

6 × 3 + 4 + 1 = 23 6 \times 3 + 4+1 =23

Noel Lo - 5 years, 12 months ago

It doesn't mention you can use brackets. You should add that to the problem.

Tom Van Lier - 5 years, 8 months ago

I dont get it. How does this come out to be 24?

Saswata Saha - 6 years ago

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How did you not get 24?

Pi Han Goh - 6 years ago

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Oh,i took it to be (1-3)/4

Saswata Saha - 6 years ago
Vraj Mistry
Jun 12, 2015

The Solution is:

this is the exact same thing i said

Ashwath Srikanthan - 6 years ago
Munem Shahriar
Nov 30, 2017

6 ÷ ( 1 3 ÷ 4 ) = 24 6 \div(1 - 3 \div 4) = 24

Hence the answer is 0120 \boxed{0120}

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