The natural shockwave
If a, b and c are three natural numbers , which of the following can never be true ?
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2 solutions
Sorry, I didn't get it. I mean in a right angled triangle,a^2 +b^2=c^2
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N not greater than 2 is satisfied. N greater than 2 not satisified. Please upvote my solution :)
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ah sorry !! I think I didn't note the entire thing...So here's an upvote:)
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@Varenya Srivastava – You should upvote the solution!!!! Not the comment please
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@Krishna Ar – Ya, actually, I could not see the option 'upvote' under your solution.....I don't know much about brilliant...kinda new:) Now I have found it..
What if a=b=c=1 ? They all are natural numbers and satisfy the option. Can you give me a triplet which satisfies a^2-b^2=c^2 where a,b, c are natural numbers. For me this is the answer.
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@Kushagra Sahni – 25-9=16.....In a right angled triangle...always hyp^2-side^2=3rd side's square
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@Varenya Srivastava – NO NO MAN. I AM NOT ASKING FOR THAT. THIS THING CAME TO MY FIND EARLIER ALSO. I AM ASKING WHAT IF A=B=C=1, THEN A^3+B^3=C^3, AND THEY ARE ALL NATURAL. SO HOW CAN THIS ANS. BE TRUE ?????
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@Kushagra Sahni – Sorry, but i don't understand you. 1^3 +1^3=2 ,, not 1^3
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@Varenya Srivastava – Ok sorry. I didn't read it carefully
OH SORRY SORRY, I UNDERSTOOD WHY THIS CAN'T BE THE ANSWER. BUT AT LEAST TELL ME WHAT IF A=B=C=1 ?
Proof by exhausion
a 2 − b 2 = c 2 there is 5 2 − 4 2 = 3 2
a 3 + b 3 = c 2 there is 1 3 + 2 3 = 3 2
a 2 + b 2 = c 3 there is 2 2 + 2 2 = 2 3
Fermat's last theorem states that no a,b,c can satisfy a n + b n = c n for n > 2