What is the maximum number of regular tetrahedra that can be placed so that they share a common edge but do not overlap?
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The dihedral angle of a tetrahedron is 7 0 . 5 2 8 7 7 9 degrees.
How did you calculate this?
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Good point, I've added this to my solution for clarity:
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Well, that is certainly a lot of steps that are left out =P
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@Pi Han Goh – Which ones? Perhaps I'll clarify the answer...
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@Geoff Pilling – Well, your working is still very condensed. From the first glance, I did not come into this problem expecting to use "coordinate geometry + dot product + I need to know what dihedral angles are".
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The dihedral angle of a tetrahedron is 7 0 . 5 2 8 7 7 9 degrees.
This can be calculated by constructing the tetrahedron as follows:
5 × 7 0 . 5 2 8 7 7 9 = 3 5 2 . 6 4 3 8 9 5
3 6 0 − 3 5 2 . 6 4 3 8 9 5 ≈ 7 . 3 6 .
So 5 tetrahedra is the most that can share an edge, as shown here: