Mrs. Sharma gave an exam in mathematics class of 5 students . She entered the scores in random order into a spreadsheet, which recalculated the class average after each score was entered . Mrs. Sharma noticed that after each score was entered, the average was always an integer. The scores were 71 , 76 , 80 , 82 , and 91 . What was the last score Mrs. Sharma entered.
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A variation of this question would be to ask for the third score entered, (answer: 91).
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Nope! Third must be 71!! I know the correct solution as well... Ill add it soon! I am currently out so just mentioned that approach!
The possible ways are (76,82,71,91,80) and (82,76,71,91,80)
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Yes, the first two scores entered must be 7 6 and 8 2 in any order, but I still think that 9 1 must be third, since then the 'running' average would be
3 7 6 + 8 2 + 9 1 = 8 3 .
If 7 1 were third then the running average would be 7 6 . 3 3 3 3 . . . . . , i.e., not an integer.
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@Brian Charlesworth – Oops!! A mistake! Sorry... You are correct!
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Sum of all scores = 4 0 0 which is divisible by 4. Now lets say last score is a , then ( 4 0 0 − a ) must be divisible by 4 (Average of 4 subjects being integer). So a must be divisible by 4.
3 chances, 2 options (76 and 80), anyone can do it right!!