Oh No, Large Squares!

Algebra Level 4

If you were only given that

43827160 6 2 = 192082000625819236 , 438271606^{2} = 192082000625819236,

can you find the sum of digits of the exact value of 56172839 5 2 561728395^{2} ?

Notes: Yes, don't use Wolfram Alpha or a calculator to solve this (though you may use a calculator to calculate the digit sum).


The answer is 91.

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1 solution

Difference of Two Squares: Let x = 561728395 x=561728395 and y = 438271606 y=438271606 x 2 y 2 = ( x + y ) ( x y ) x^2-y^2=(x+y)(x-y) 56172839 5 2 43827160 6 2 = ( 561728395 438271606 ) ( 561728395 + 438271606 ) 561728395^2-438271606^2=(561728395-438271606)(561728395+438271606) 56172839 5 2 43827160 6 2 = 123456789123456789 561728395^2-438271606^2=123456789123456789 56172839 5 2 = 315538789749276025 561728395^2=315538789749276025

Nice one!! Upvoted!!

Pranjal Jain - 6 years, 6 months ago

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Thanks :) I think that the problem was nicer though :D

Marc Vince Casimiro - 6 years, 6 months ago

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Exactly! Nice problem!

Pranjal Jain - 6 years, 6 months ago

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@Pranjal Jain Thanks! :)

Steven Yuan - 6 years, 6 months ago

That was exactly what I did! cool... I mean the coincidence!

Sravanth C. - 6 years, 4 months ago

I have the same approach also

Prokash Shakkhar - 4 years, 4 months ago

Coincidence

Debarghya Adhikari - 2 years, 1 month ago

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