This looks reasonable...(4)
Can a unit cube be sliced into six congruent tetrahedrons?
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2 solutions
The cube satisfies 0 < x < 1 , 0 < y < 1 , 0 < z < 1
Then slice the cube into six:
0 < x < y < z < 1
0 < x < z < y < 1
0 < y < x < z < 1
0 < y < z < x < 1
0 < z < y < x < 1
0 < z < x < y < 1
nice profile pic
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I too changed my profile pic.
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I think it is the old one
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@Mohammad Farhat – Yes. In between I have changed it to Aryabhatta as he is my role model.
X X! cool pic
First cut an unit cube in half so that each half has 2 square faces and 2 half square faces, besides the cut face. Divide the 2 square faces into 2 half square faces, so that there are 6 half square faces. Use them in pairs to make 3 identical irregular tetrahedra. Do the same for the other half of the cube. Congruent includes mirror images.