If x > 2 and 2 x = x 2 , what is the value of x 2 ?
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Why is there no other solution? I am just curious.
So we don't worry so much about x>2 to start with so then what we do is
2 x = x 2
so
x = 2 x
so
x = 2 2 2 x
and we find solutions to this and one of them is 4
and 4 > 2
and 4 2 = 1 6
so the answer is 16
Is this the only solution?
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@Pi Han Goh Yes, it is the only real solution for x>2. There are no imaginary solutions. There are also no complex solutions.
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@Pi Han Goh I forgot to add, ∞ but not -∞ because the limit as x→∞ 2^x = lim x→∞ x^2
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@Chase Marangu – The question already stated that x > 2 , so it's a real number. But how do you know that there isn't any other (real) solution?
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@Pi Han Goh – The function is continuous and erm...simple(?) I guess? Don't know if that's a actual mathematical thing. The apparent pattern is that √(2ˣ) > x for all x>4. Then at infinity 2^∞ = ∞^2 so you get another solution there. And you can say that infinity isnt a real number but sometimes I like to pretend. I mean it's not a number anyways but still.
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