∫ − 1 0 1 − x 1 + x d x
If the value of the integral above equals to B A ( π − B ) for positive integers A and B , find the value of A + B .
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Nice solution but is there any way to know what are we supposed to substitute since we got a lot of options ?
How did you get the limits as (1.414) & [1]..?Please explain?
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That is because of substitution !!
1 - 0 =t^{2} => t = 1
1- (-1) = t^{2} => \sqrt{2}
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Ohh..gr8 thanx a lot !..:)
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@Yuki Kuriyama – no problem, I am glad it helped . :D
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Let 1 − x = t 2 then proceed to simple integration of
2 ∫ 1 2 2 − t 2 d t
The final answer is 2 1 ( π − 2 )