Find the smallest prime number n , such that for all prime numbers p ≥ n , p 2 + 2 is always composite.
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Even though I guessed between 4 and 5, I think the answer should be 4 since it doesn't specify n has to be a prime and p ≥ 4 makes sense.
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But p is a prime and cannot take the value of 4 . So it's not necessary to say n has to be a prime.
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4 is the smaller value of n than 5 and it still works (so the answer would be 4 - the problem asked for the smallest value of n , and 4 works), because the set of all primes ≥ 4 is equal to the set of all primes ≥ 5 . But now the problem statement has been edited and it says that n is prime, so the answer 5 is now correct.
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@Mathh Mathh – I still have doubt on this one, I don't know. Maybe one of challenge masters will clarify this for us?
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@Kazem Sepehrinia – Thanks. Those who answered 4 have been marked correct.
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For p ≥ 5 we have p 2 ≡ 1 mod 3 and therefore p 2 + 2 ≡ 1 + 2 ≡ 0 mod 3 and p 2 + 2 is always composite. So n m i n = 5 . Note that for p = 3 , p 2 + 2 = 1 1 is a prime.