Too many celebrations going around

Algebra Level 1

If someone tells you y = ln ⁡ ( x m − a s ) r 2 , y = \frac{ \ln \left( \frac{x}{m} - as \right) } { r^2 },

what is he saying?

Merry Christmas Happy Hanukkah Happy New Year Feliz Navidad

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Calvin Lin by Calvin Lin

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23 solutions

Discussions for this problem are now closed

Michael Mendrin
Dec 24, 2014

Okay, a little foodling around explains this one

y r 2 = l n ( x m − a s ) y{ r }^{ 2 }=ln\left( \dfrac { x }{ m } -as \right)
e r r y = ( x m − a s ) { e }^{\displaystyle rry }=\left( \dfrac { x }{ m } -as \right)
m e r r y = x − m a s m{ e }^{\displaystyle rry }=x-mas

198 Helpful 0 Interesting 0 Brilliant 0 Confused

I really like this question because it includes some fun into a difficult math problem.

Daniel Park - 6 years, 5 months ago

This question is v nice

Huma Naaz - 6 years, 5 months ago

Step by step....we move to marry x-mas Bingo !! Nice thought ....

Ashok Navale - 6 years, 5 months ago

i really love this instead of merry christmas i will write this equation in cards

mika servi - 6 years, 4 months ago

very good this quistion is very hard

irshad khan - 6 years, 5 months ago
Jack Rawlin
Dec 24, 2014

The equation just needs to be re-arranged

y r 2 = I n ( x m − a s ) yr^2 = In (\frac {x}{m} - as)

Since e I n ( x ) = x e^{In(x)} = x

e r 2 y = x m − a s e^{r^2y} = \frac {x}{m} - as

e r r y = x − m a s m e^{rry} = \frac {x-mas}{m}

m e r r y = x − m a s me^{rry} = x-mas

After that I'd would just like to say

y = I n ( x m − a s ) r 2 y = \frac {In(\frac {x}{m} - as)}{r^2} to you too and a happy n = e y e a r ⋅ w ) e 2 w 2 n = \frac {ey^{e}a^r \cdot w)}{e^2w^2}

41 Helpful 0 Interesting 0 Brilliant 0 Confused

I bcame vry xcitd to c da solution...cuz til nw I m aquintd wid such sums..realy thnx a lot..I wil be obiligd if u keep on guiding lyk dis. @Calvin Lin

Chandril Banerjee - 6 years, 5 months ago

:) mee too...

Manikanta Yerraguntla - 6 years, 5 months ago

Just a small typo but surely you mean \­[­ e^{ln(x)} = x \­]

Also someone please tell me how LaTex works because I have no idea haha >_<

Shinichi Hirata - 6 years, 5 months ago

I've taken note and I've changed the solution so that it shows e I n ( x ) = x e^{In(x)} = x rather than e I n ( x ) = e x e^{In(x)} = e^x .

About that LaTeX question, I can't explain how it works but there's a guide on it here .

Jack Rawlin - 6 years, 5 months ago

Cheerio :)

Shinichi Hirata - 6 years, 5 months ago

@Shinichi Hirata – Go to this link. It might help you in your LaTeX \LaTeX struggle. :P

Prasun Biswas - 6 years, 5 months ago

@Prasun Biswas – Thank you :)

Shinichi Hirata - 6 years, 5 months ago

@Shinichi Hirata – You're welcome. :)

Prasun Biswas - 6 years, 5 months ago

Please expand this...happy n=....as u hv given...I want to wish evry1 happy nw year using dis as i guess dat is nly hidden withn it 😉 @Jack Rawlin

Chandril Banerjee - 6 years, 5 months ago

Alright

But first

I just noticed this but I meant to write

n = e y e a r ⋅ w e 2 w 2 n = \frac {ey^ea^r \cdot w}{e^2w^2} rather than what I put. So I'll edit it straight away.

n = e y e a r ⋅ w e 2 w 2 n = \frac {ey^{e}a^{r} \cdot w}{e^{2}w^{2}}

Multiply by e 2 w 2 e^2w^2

n e 2 w 2 = e y e a r ⋅ w ne^{2}w^{2} = ey^ea^r \cdot w

e y e a r ⋅ w ey^ea^r \cdot w can be written as e w ( y e a r ) ew(y^ea^r)

n e 2 w 2 = e w ( y e a r ) ne^2w^2 = ew(y^ea^r)

Divide by e w ew

n e 2 w 2 e w = y e a r \frac {ne^2w^2}{ew} = y^ea^r

n e w = y e a r new = y^ea^r

So

y = I n ( x m − a s ) r 2 y = \frac {In(\frac {x}{m} - as)}{r^2} to you too and a happy n = e y e a r ⋅ w e 2 w 2 n = \frac {ey^{e}a^{r} \cdot w}{e^{2}w^{2}}

Means

m e r r y = x − m a s me^{rry} = x-mas to you too and a happy n e w = y e a r new = y^ea^r

Jack Rawlin - 6 years, 5 months ago
Parag Zode
Dec 25, 2014

20 Helpful 0 Interesting 0 Brilliant 0 Confused
Deepanshu Gupta
Dec 24, 2014

It was just tangent over my Head , But I guess Answer By thinking that Nearest Festival is Christmas , and It works :)

what is actual solution ??

4 Helpful 0 Interesting 0 Brilliant 0 Confused

All of those festivals are around the corner.

In fact, Feliz Navidad means Merry Christmas in Spanish.

Calvin Lin Staff - 6 years, 5 months ago

I can make a meaning out of that word. There was a boy whose name was Feliz and his dad had a job in the navy. Hence, Feliz Navidad :P

Prasun Biswas - 6 years, 5 months ago

ohh I didn't understand the other Languages , So I have choose this (As I say I just Guess the answer) :):)

But Thanks ! For this Kind of info !

and will I delete this solution ?

Deepanshu Gupta - 6 years, 5 months ago

Nah, don't worry about it. This is meant as a fun question, and I'm glad we're all having fun.

Calvin Lin Staff - 6 years, 5 months ago

@Calvin Lin – ! ⌣ ¨ \ddot\smile ! ⌣ ¨ \ddot\smile ! ⌣ ¨ \ddot\smile

! ⌣ ¨ \ddot\smile ! ⌣ ¨ \ddot\smile ! ⌣ ¨ \ddot\smile

Deepanshu Gupta - 6 years, 5 months ago

@Deepanshu Gupta – Used to sing carols having the word "Feliz navidad " when i was young. Got to Know the meaning today ! thanks @Calvin Lin

Keshav Tiwari - 6 years, 5 months ago

@Keshav Tiwari – FYI: "próspero año y felicidad" means "a prosperous year and happiness".

See Wikipedia .

Calvin Lin Staff - 6 years, 5 months ago

@Calvin Lin – is it possible to form happy new year as an equations ?

Alok patel - 6 years, 5 months ago

@Alok Patel – Yes of course, why don't you give it a try?

Calvin Lin Staff - 6 years, 5 months ago

@Calvin Lin – Thank you ! Merry Christmas ! :D

Keshav Tiwari - 6 years, 5 months ago

Found the word y = l o g ( x − m a s ) − l o g m r 2 y = \dfrac{log(\boxed{x - mas}) - logm}{r^2} , yes what is the solution?

U Z - 6 years, 5 months ago

I too did exactly the same way

Kushal Patankar - 6 years, 5 months ago

m e r r y x − m a s me^{rry} \quad x-mas . Just change the subject to y.

Sudeep Salgia - 6 years, 5 months ago

great ! ⌣ ¨ \ddot\smile

Deepanshu Gupta - 6 years, 5 months ago
Sharon Lin
Dec 25, 2014

Simply re-arrange the variables in the equation until you find something that looks a bit like a holiday greeting:

Season's Greetings to everyone else, as well!

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Hafsa Amanullah
Dec 24, 2014

its just cross multiplication and then simplification

2 Helpful 0 Interesting 0 Brilliant 0 Confused
Frank Jackson
Dec 27, 2014

feliz navidad should also be acceptable lol

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Gobai Jogo
Dec 27, 2014

1 Helpful 0 Interesting 0 Brilliant 0 Confused

I selected this option because after solving the sum, I got me^rry=x-mas

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Gamal Sultan
Dec 26, 2014

r^2 y = ln(x/m -as)

e^rr y = x/m - as

me^rr y = x-mas merry christmas

1 Helpful 0 Interesting 0 Brilliant 0 Confused

This question is the hardest question ever seen.

I almost ended up at Happy Halloween and Happy Valentine though. -__-"

1 Helpful 0 Interesting 0 Brilliant 0 Confused
Mahbub Babui
Jan 20, 2015

Really an interesting question. Liked it

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Souvik Nath
Jan 11, 2015

0 Helpful 0 Interesting 0 Brilliant 0 Confused

x/m - as = christmas

0 Helpful 0 Interesting 0 Brilliant 0 Confused

connect the letters in the equation after simplifying and correlate with the letters in the option of answers

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Newaz Sharif
Jan 6, 2015

Its really a great fun by doing this kinds of math, i like it...:)

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Samir Saïdi
Jan 6, 2015

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Maxwell Aladago
Jan 4, 2015

that was really interesting. it feels good to use math for fun activities like these

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Harsh Kumar
Jan 4, 2015

I just chose Merry Christmas cause its Christmas :D

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Shashank Jain
Jan 1, 2015

yrr= ln((x-mas)/m) e^yrr={x-mas}/m me^rry=x-mas.....merry=x-mas :D

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Troilus Llacuna
Dec 31, 2014

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Hajra Malik
Dec 30, 2014

As e^{ln(x)}=x so, yr^{2}=ln(x\m-as) e^{rry}=e^{ln(x\m-as)} me^{rry}=x-mas

0 Helpful 0 Interesting 0 Brilliant 0 Confused
Anna Anant
Dec 26, 2014

yr^2 = ln(x/m-as) e^r^2y = x/m - as e^rry = (x-mas)/m me^rry = x-mas merry = x-mas

0 Helpful 0 Interesting 0 Brilliant 0 Confused

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