Transcendence

Algebra Level 5

A complex number α C \alpha \in\ \mathbb{C} is called algebraic if there is a non-zero polynomial P ( x ) Q [ x ] P(x) \in \mathbb{Q[x]} with rational coefficients such that P ( α ) = 0 P(\alpha) = 0 .

Which of the following statements is correct?

\quad A: There are only finitely many algebraic numbers.

\quad B: All complex numbers are algebraic.

\quad C: sin ( π 3 ) + cos ( π 4 ) \sin(\frac{\pi}{3}) + \cos(\frac{\pi}{4}) is algebraic.

\quad D: A , B , C A,B,C are all correct.

\quad E: None is correct

D E B C A

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1 solution

Mark Hennings
Jun 29, 2017

Every rational is algebraic, so there are an infinite number of algebraic numbers. The number e e is transcendental, so not all complex numbers are algebraic (in fact, there are only countably many algebraic numbers). The algebraic numbers form a subfield of C \mathbb{C} , and so sin 1 3 π + cos 1 4 π = 1 2 ( 3 + 2 ) \sin\tfrac13\pi + \cos\tfrac14\pi = \tfrac12(\sqrt{3}+\sqrt{2}) is algebraic, since 2 \sqrt{2} and 3 \sqrt{3} are both algebraic. Thus C \boxed{C} is the only true statement.

Is there an easy way to explain or show why algebraic numbers are closed under addition?

Michael Mendrin - 3 years, 11 months ago

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The simplest way uses field extensions, where u u is algebraic if and only if [ Q [ u ] , Q ] [\mathbb{Q}[u],\mathbb{Q}] is finite. If u , v u,v are both algebraic, then [ Q [ u , v ] , Q ] [\mathbb{Q}[u,v],\mathbb{Q}] is finite, and Q [ u , v ] \mathbb{Q}[u,v] contains both u + v u+v and u v uv .

Mark Hennings - 3 years, 11 months ago

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This is probably a good example of why an unavoidable level of abstraction can be necessary to explain certain phenomenon in physics. I'm going to keep this example in mind the next time I get into this sort of argument about "why does physics have to be so complicated and hard to understand?"

Michael Mendrin - 3 years, 11 months ago

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@Michael Mendrin Of course, for this question, we could just have exhibited the minimum polynomial of 2 + 3 \sqrt{2}+\sqrt{3} , namely X 4 10 X 2 + 1 X^4 - 10X^2 + 1 .

Mark Hennings - 3 years, 11 months ago

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@Mark Hennings That would be like using a particle accelerator to discover that there are particles. We'd like to understand more.

Michael Mendrin - 3 years, 11 months ago

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