How does this relate to Pie?

We know that $x \neq 0$ in this problem, so we can multiply both sides by $x^{3}$ . The equation will become

$x^{2} + x + 1 = \sqrt{3.1415926}x^{3}$

$\sqrt{3.1415926}x^{3} - x^2 - x - 1 = 0$

$\displaystyle x = \sqrt[3]{\sqrt{{\frac{25000000000000000\sqrt{78539815}}{313938535322392905133107}}+\frac{799668057500000000\sqrt{78539815}}{313938535322392905133107}+\frac{182964583750000}{2220660914484321}}+\frac{500\sqrt{78539815}}{15707963}+\frac{5000000000\sqrt{78539815}}{6661982743452963}+\frac{2500000}{47123889}} + \sqrt[3]{-\sqrt{{\frac{25000000000000000\sqrt{78539815}}{313938535322392905133107}}+\frac{799668057500000000\sqrt{78539815}}{313938535322392905133107}+\frac{182964583750000}{2220660914484321}}+\frac{500\sqrt{78539815}}{15707963}+\frac{5000000000\sqrt{78539815}}{6661982743452963}+\frac{2500000}{47123889}} + \frac{1000\sqrt{78539815}}{47123889}$

$\displaystyle x = \frac{1000\sqrt{78539815}}{47123889} + \frac{\sqrt{3}\sqrt[3]{\sqrt{{\frac{25000000000000000\sqrt{78539815}}{313938535322392905133107}}+\frac{799668057500000000\sqrt{78539815}}{313938535322392905133107}+\frac{182964583750000}{2220660914484321}}+\frac{500\sqrt{78539815}}{15707963}+\frac{5000000000\sqrt{78539815}}{6661982743452963}+\frac{2500000}{47123889}} + \sqrt[3]{-\sqrt{{\frac{25000000000000000\sqrt{78539815}}{313938535322392905133107}}+\frac{799668057500000000\sqrt{78539815}}{313938535322392905133107}+\frac{182964583750000}{2220660914484321}}+\frac{500\sqrt{78539815}}{15707963}+\frac{5000000000\sqrt{78539815}}{6661982743452963}+\frac{2500000}{47123889}}}{2}i$

$\displaystyle x = \frac{1000\sqrt{78539815}}{47123889} - \frac{\sqrt{3}\sqrt[3]{\sqrt{{\frac{25000000000000000\sqrt{78539815}}{313938535322392905133107}}+\frac{799668057500000000\sqrt{78539815}}{313938535322392905133107}+\frac{182964583750000}{2220660914484321}}+\frac{500\sqrt{78539815}}{15707963}+\frac{5000000000\sqrt{78539815}}{6661982743452963}+\frac{2500000}{47123889}} + \sqrt[3]{-\sqrt{{\frac{25000000000000000\sqrt{78539815}}{313938535322392905133107}}+\frac{799668057500000000\sqrt{78539815}}{313938535322392905133107}+\frac{182964583750000}{2220660914484321}}+\frac{500\sqrt{78539815}}{15707963}+\frac{5000000000\sqrt{78539815}}{6661982743452963}+\frac{2500000}{47123889}}}{2}i$

Plugging in the question for every values we get for sure, we get

$\sqrt{(x^{2015}\times x^{2010})\times(x^{-1945}\times x^{-2080})} = \sqrt{x^{2015+2010-1945-2080}} = \sqrt{x^{0}} = \sqrt{1} = \boxed{1}$ ~~~

lol

$2015+2010-1945-2080=0$ Thus, $\sqrt{x^0}=1$

The given expression = square root of[x^(2015 + 2010 - 1945 - 2080)] =

square root of[x^0] = 1

2015+2010-1945-2080=0 Therefore, x^0 = 1

irrespective of given condition. ans :-x^(4025-4025)= x^0=1

I'm quite shocked when I see this is level 1

It turns out doesn't have to do with pi

it's still easy

4025-4025=0; anything power 0=1; so x power 0 also=1; and sqr root of 1 is 1. so the answer is 1.

x^(2015+2010)=x^4025 ; x^(-1945+-2080)=x^-4025 , multiplying we will get 1 and √1=+-1

Rules of exponents. Enough said.

multiply them not more than that