Over all angles A , B , C of an acute triangle, find the minimum value of
2 0 2 0 ∑ sin B + sin C − sin A sin A
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This is a good start. However, your explanation has a slight gap, which is a common misconception made with inequalities.
Keep writing more solutions and you will get the hang of this!
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"you will get hang of this"
Sir i cannot understand by this line. What do you mean?
Should i show the equality case also?
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It means that you will be able to write good solutions by keep writing more solutions over time.
Yes, you should show that the minimum value is attainable. i.e.: when A = B = C = 6 0 ∘ .
I agree that this has a good start, but your explanation has some gaps that need filling in:
[1] What motivates you to use the substitution x = b + c − a , y = c + a − b , z = a + b − c in the first place? It appears that you have written a bunch of prefabricated steps which removes the mystery behind the problem.
[2] It is also worth clarifying why the denominator of the fraction in the given cyclic sum is never zero, otherwise, the sum can be undefined.
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The substitution i did was to make the expression much simpler so that i can use AM-GM, Titu's lemma etc inequalities with ease.
I am working on my solution. I will modify it later.
Try this also.
https://brilliant.org/problems/korea-proposal-to-imo/?ref_id=1266863
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By sine rule
∑ sin B + sin C − sin A sin A = ∑ b + c − a a .
Now, let
x = b + c − a y = c + a − b z = a + b − c .
Substituting it the inequality to be solved becomes
∑ 2 x y + z , whose minimum value by AM-GM is 3 .
Thus,,
2 0 2 0 ∑ sin B + sin C − sin A sin A ≥ ( 2 0 2 0 × 3 ) = 6 0 6 0