Trigono problem!

Geometry Level pending

The sum of least and greatest possible value of 24 sin theta + cos theta (Round the answer to integer)


The answer is 0.

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2 solutions

Ashish Menon
Jul 16, 2016

For any equation a sin θ + b cos θ a \sin\theta + b \cos\theta , the maximum and minimum values are a 2 + b 2 \sqrt{a^2 + b^2} and a 2 + b 2 -\sqrt{a^2 + b^2} which on addition gives 0 \color{#3D99F6}{\boxed{0}} .

Prince Loomba
Feb 9, 2015

-(577)^(1/2)+(577)^(1/2)

Note that 24 sin θ + cos θ = 2 4 2 + 1 2 sin ( θ + α ) 24 \sin \theta + \cos \theta = \sqrt{ 24^2 + 1^2 } \sin ( \theta + \alpha) , where tan α = 1 24 \tan \alpha = \frac{1}{24} .

Hence, the maximum is 2 4 2 + 1 2 \sqrt{ 24 ^ 2 + 1^2} and the minimum is 2 4 2 + 1 2 - \sqrt{ 24^2 + 1^2 } , and the sum is 0.

I have updated the answer to 0.

Calvin Lin Staff - 6 years, 4 months ago

why can't sin theta be negative?

Calvin Lin Staff - 6 years, 4 months ago

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the minimum value of a sin theta + b cos theta is -(a^2+b^2)^(1/2) and max (a^2 + b^2)^(1/2)

Prince Loomba - 6 years, 4 months ago

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No, that is not true. What happens when θ = π 2 \theta = - \frac{\pi}{2} in your scenario?

Calvin Lin Staff - 6 years, 4 months ago

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@Calvin Lin Sorry i have changed the answer to 0 but the max and min values are as stated

Prince Loomba - 6 years, 4 months ago

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@Prince Loomba I'm responding because you used the word "but", which sounds to me that you are disagreeing with what I said. If this is not the case, ignore this comment.

You were claiming that the minimum of 24 sin θ + cos θ 24 \sin \theta + \cos \theta is 2 4 2 1 2 \sqrt{24 ^ 2 - 1 ^ 2} . What is the value of the expression when θ = 0 \theta = 0 ? Or when θ = 18 0 \theta = 180 ^ \circ ?

Calvin Lin Staff - 6 years, 4 months ago

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@Calvin Lin Max value: (577^(1/2)) and Min value: -(577^(1/2))

Prince Loomba - 6 years, 4 months ago

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