k = 1 ∏ 1 0 0 [ 1 + 2 cos ( 3 1 0 0 + 1 2 π ( 3 k ) ) ] = ?
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my work was more tedious :(
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My work is the lazy one. I like simple solutions but I enjoy a lot the long hard ones written by others :)
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btw i am very poor in latex ,, thus i cannot upload the solution .. :(
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@Rudraksh Sisodia – No worries, I just learnt Latex few months ago, I totally understand how does it feel to write complicated symbols using Latex. It is painful :)
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We know the c o s part is going to 0 at some point because c o s 2 π = 0 ,so we are left with the product of 1 by itself 1 0 0 times= 1