A geometry problem by Rudraksh Sisodia

Geometry Level 4

k = 1 100 [ 1 + 2 cos ( 2 π ( 3 k ) 3 100 + 1 ) ] = ? \large \prod_{k=1}^{100} \left[1+2\cos\left(\frac{2\pi(3^k)}{3^{100}+1}\right)\right] = \, ?


The answer is 1.

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1 solution

Hana Wehbi
Aug 27, 2016

We know the c o s cos part is going to 0 0 at some point because c o s π 2 = 0 cos \frac{\pi}{2}=0 ,so we are left with the product of 1 by itself 100 100 times= 1 1

my work was more tedious :(

Rudraksh Sisodia - 4 years, 9 months ago

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My work is the lazy one. I like simple solutions but I enjoy a lot the long hard ones written by others :)

Hana Wehbi - 4 years, 9 months ago

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btw i am very poor in latex ,, thus i cannot upload the solution .. :(

Rudraksh Sisodia - 4 years, 9 months ago

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@Rudraksh Sisodia No worries, I just learnt Latex few months ago, I totally understand how does it feel to write complicated symbols using Latex. It is painful :)

Hana Wehbi - 4 years, 9 months ago

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