trolled you all..

Level 2

first calculate the value of this integral:-

[ l o g ( e ζ 2 + 1 ) + 2 ( e ζ 2 ( 2 ζ 1 ) 1 ( e ζ 2 + 1 ) 7 ) ] d ζ \int { [log({ e }^{ { \zeta }^{ 2 } } } +1)+2(\frac { { e }^{ { \zeta }^{ 2 } }(2\zeta -1)-1 }{ { { (e }^{ { \zeta }^{ 2 } }+1) }^{ 7 } } )]\quad d\zeta

let it be" Q"

now consider this :-

1 2 Q x d x \int _{ 1 }^{ 2 }{ \frac { Q }{ x } } dx

whats the answer of this integral-

Hint:- THINK!!!!!!

This is an entry in the troll king contest \text{ This is an entry in the troll king contest}

none of these 8 0 3 Q

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1 solution

Soumya Dubey
Mar 20, 2015

the answer is Q because:-

the Integral symbol was too tired after performing the first big huge Integral and hence did not consider carrying out the second integral and hence the answer is "Q" only.

since it is a troll question please do not take the answer seriously..

Wait ... What ??

A Former Brilliant Member - 6 years, 2 months ago

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It is not troll ,It is thinking not at all. XD!1

Gautam Sharma - 6 years, 2 months ago

wait didn't u like the solution .or else if it violates the rules of competition i can remove it at once .no problem.

Soumya Dubey - 6 years, 2 months ago

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This is totally meaningless! Since Q is not a function of x, it can simply be taken out of the integral sign and it gives Qln2, not Q!

Satyam Bhardwaj - 6 years, 2 months ago

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@Satyam Bhardwaj i am familiar with the rules of integrals and since this was a troll question i need not stress upon the fact of carrying out the all operations .or else i could have changed the question to solve the first integral only "which is needless to say i havent stressed myself in trying it out" .this is troll question just take up the fun fact and forget the seriousness of maths for the sake of this question

Soumya Dubey - 6 years, 2 months ago

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@Soumya Dubey Agreed that this is a troll and you wanted us to enjoy it . But I don't think everyone will interpret it in the way you intend them to do so .

Btw , I cannot say anything about deleting this question . It's your question and hence it's your call .

I might suggest you wait for response from the community before you do anything .

A Former Brilliant Member - 6 years, 2 months ago

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@A Former Brilliant Member okay cool :)

Soumya Dubey - 6 years, 2 months ago

i was like ...Really ? after seeing your solution. Maths would have retired by now.XD

Gautam Sharma - 6 years, 2 months ago

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yeah completly out of track solution...well this is troll i guess.u think one way but the answer is another way.:p

Soumya Dubey - 6 years, 2 months ago

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