without filling. The cross section of the right hand of the tube is twice the cross section of the left one. Water is then poured water on the right hand of the tube until the water level reaches the top of the right side. If the level of mercury in the left side of the tube rises a distance
A U-tube is filled with mercury as shown below, leaving a distance
where and are positive co-prime integers, find the value of .
Take the density of mercury to be 13.6 times the density of water.
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The cross section of left tube is half that of right tube. So, if mercury rises by x on left tube, mercury level falls by 2 x on the other.
So, the total height of water column is a + 2 x
Now, at equilibrium, pressure at point A should be equal to pressure at point B.
P A = P 0 + (a + 2 x ) * 1 * g + (L - 2 x ) * 13.6 * g
P B = P 0 + (x + L) * 13.6 * g
Equating P A and P B and solving,
we get x = ( 1 9 9 1 0 ) a.