There is one non-negative integers x that satisfy
x 3 + ( x + 1 ) 3 + ( x + 2 ) 3 + ⋯ + ( x + n ) 3 = ( x + ( x + 1 ) + ( x + 2 ) + ⋯ + ( x + n ) ) 2
For any positive integer n > 1
Find that x and write the value of x as answer.
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Btw what is the relevance of the title? Just curious...
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Nothing can't think of any title
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I've a suggestion: identically equal
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@Agent T – I edited. Ok thank you
Man, what happened to your ultra-cool Sunglasses Avatar, Agent-Tee???!!!
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Haha! Lemme change back to my ultra cool sunglasses avatar ;)
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@Agent T – Keep those weird physics contraption probs comin' too!!! :) Have a good day....
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@Tom Engelsman – Hey I have posted one more , hope you like it :D ! You too have an amazingly awesomee day!!
Wait... x=1 works too!
And x=1 is incorrect for some reason...
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Summation of n terms = 2 n ( n + 1 )
And summation of first n 3 terms= ( 2 n ( n + 1 ) ) 2
This will only be valid here when x = 0
Boom!