Unreliable clock

Yes , I can't enter on slack on my given email address because I had to be so to say "prevented" publishing a correct and clear problem on Brilliant .I suppose calvin tried to "exile" me from brilliant definitely but on the moment such a thing didn't work as I made another account and I'm still waiting a reply from Sue Khim relating to this situation which , unfortunately , from some reason she doesn't seem though to be willing to give anyway.

That was the initial message I wrote you. But I realized though I can't post messages so I made some changes to be able. Actually now I know why , because she agrees with Calvin and lack any sort of reasoning and sense of things seemingly. They seem to have banned me such that I can't use any button for posting messages or such stuff so unfortunately I suppose I am going to be so to say banned after all but don't worry Prince , such injustice and stupidity will get some day a reply from me I suppose though nonsense doesn't deserve it. We can still talk though on email if you want , I'm sorry I can't be on slack any longer haha. It was fun speaking with you Prince and others so please say goodbye from me to the community so to say if you want to , it seems here you can't publish problems freely or the free speech isn't at all important for such idiots and superficiial person like calvin so to say but anyway.

You can calculate the passed time in some other way but first we need to point out that the problem works on the assumption that the increase in time and error of the clock is done for in a continous way for every conceivable and finite unit of time and that the clock doesn't gain magically 15 minutes at every hour and measures until a 1 hour passes right. Because we admit that at any unit of time there is some increase we can calculate that for any minute since the clock gains 15 minutes per 60 minutes or 1 hour the shows with 15/60=0,25 more minutes than the ones which actually passed which means that if the clock shows some accumulated number of minutes A , A = m+m*0,25. This can be read as saying that for m minutes passed for each minute the clock adds a quarter of a minute. In the particular case of 3 hours which are 180 minutes we have that 180= m(1+0,25) therefore that the number m = 180/1,25 which is 144 minutes from which we get the result anyway.