Varring Acceleration

Classical Mechanics Level 4

A body started from rest at t=0s acceleration is zero and at t=10s acceleration is 15 m/s²

Find the power at t=10s.

Details and Assumptions

  • Mass of body = 5kg

  • Acceleration varies linearly with time.


The answer is 5625.

Mitesh Warang by mitesh warang , 23, India

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3 solutions

Mitesh Warang
Jul 4, 2014

Acceleration is various with time

Therefore I can write it as a = z × t {a=z×t}

Where t = {t=} time and z = {z=} some constant of linear variation

Therefore power at t = 10 s {t=10s}

Power = Force×Velocity

Power= 5625

Power only at t=10s

Decimal up to two digit is to mislead you

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If any one has doubt reply to this

mitesh warang - 6 years, 9 months ago

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I think you should mention in the question that acceleration varies linearly with time so that we don't have to assume.

Rahul Badenkal - 5 years, 11 months ago

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Hi friend as i mention in the question at start acceleration is zero and at the end it is 15 then you must come to know that acceleration is varring with time

mitesh warang - 5 years, 11 months ago

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@Mitesh Warang – What I am saying is you should mention it varies LINEARLY with time . Otherwise a = 0.15t^2 also satisfies the conditions in your question but giving different answer

Rahul Badenkal - 5 years, 11 months ago

friend to find acceleration varies linear time time is challenge that you have to find out so no need of mention it

mitesh warang - 5 years, 11 months ago

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@Mitesh Warang – You need to add that the acceleration varies linearly with time.

Miloje Đukanović - 5 years, 7 months ago

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@Miloje Đukanović – question is perfect you must understand how accelartion, time and velocity are varing.

mitesh warang - 5 years, 6 months ago

How did u find the velocity

David Ibrahim - 6 years, 9 months ago
Aaditya Lanke
Jan 4, 2017

velocity of the body at 10s= 150 m/s Momentum of the body at 10s= 750

KE at 10 s= p^2/2m=750^2/10=56250

P= KE/t=56250/10=5625 W

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Rifath Rahman
Sep 17, 2014

P=W/t=(Fs)/t=(mas)/t,now s=ut+1/2 * at^2=1/2 * at^2[as u=0]=1/2 * 15 * 10^2=750.So P=(5 * 15 * 750)/10=75 * 75=75^2=5625 W

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