Velocity and work?

When a body is acted upon a force of ( 5 i ^ + 4 j ^ 3 k ^ ) N \left(5\hat{i} + 4\hat{j} - 3\hat{k}\right)\text{ N} , it begins to move with a constant velocity of ( 2 i ^ 3 j ^ 7 k ^ ) m/s \left(2\hat{i} - 3\hat{j} - 7\hat{k}\right)\text{ m/s} . Find the work done(in joules) by the force after 4 seconds.


The answer is 76.00.

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1 solution

Ashish Menon
Jul 5, 2016

P = F v = ( 5 i ^ + 4 j ^ 3 k ^ ) ( 2 i ^ 3 j ^ 7 k ^ ) = 10 12 + 21 = 19 watts W = P × t = 19 × 4 = 76.00 J \begin{aligned} \vec{P} & = \vec{F} \cdot \vec{v}\\ \\ & = \left(5\hat{i} + 4\hat{j} - 3\hat{k}\right) \cdot \left(2\hat{i}- 3\hat{j} - 7\hat{k}\right)\\ \\ & = 10 - 12 + 21\\ \\ & = 19 \text{watts}\\ \\ \therefore W & = P × t\\ \\ & = 19 × 4\\ \\ & = \color{#3D99F6}{\boxed{76.00 J}} \end{aligned}

Nice solution.. but can we do it directly without finding the power ? W = F s W = ( F v ) × t \text{Nice solution.. but can we do it directly without finding the power ? } \\ W = \vec{F}\cdot\vec{s} \implies W = \left( \vec{F}\cdot\vec{v} \right) \times t

Sabhrant Sachan - 4 years, 11 months ago

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No, that makes f,v,t scalar product :P It works if we calculate the dot product first and then multiply the numerical answer we obtain with the numerical time.

Ashish Menon - 4 years, 11 months ago

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Easy one but it's Level 3 :)

Abhiram Rao - 4 years, 11 months ago

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@Abhiram Rao Thanks! Dont worry about the level, it automatically changes with the number of correct answerers :)

Ashish Menon - 4 years, 11 months ago

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@Ashish Menon The first Level 4 Classical Mechanical Problem I solved :)

Abhiram Rao - 4 years, 11 months ago

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@Abhiram Rao brilliant is an excellent place to learn , diverse and beautiful minds from all over the place will help you to develop your skills , soon you will be able to solve level 5 problems as well :)

Ujjwal Mani Tripathi - 4 years, 10 months ago

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@Ujjwal Mani Tripathi Very inspiring :)

Ashish Menon - 4 years, 10 months ago

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@Ashish Menon thank you , i shared my experience i have been on brilliant since 4 years from the right start , in the starting i was on level 2 in all the topics but continuous learning helped me level up my maths , by the way your physics questions are cool .

Ujjwal Mani Tripathi - 4 years, 10 months ago

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@Ujjwal Mani Tripathi Thanks, so you are a very old user, nice to meet you.

Ashish Menon - 4 years, 10 months ago

@Abhiram Rao Congrats!!

Ashish Menon - 4 years, 11 months ago

@starwar clone Thanks a lot for your advice! And @Ashish Siva How are you ? Been a very long time

Abhiram Rao - 4 years, 10 months ago

My doubt is can we find displacement by s(vector)=v(vector) x time then W =F.s ??

Jus Jaisinghani - 4 years, 11 months ago

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Well since time has no i ^ \hat{i} , j ^ \hat{j} and k ^ \hat{k} you might be asking to multiply the magnitude of the velocity vector and obtain the magnitude of the displacement vectorw. Well, I am not sure that qill work becayse it corresponds(likely) to cross product but we need the dot product. The last time I tried that methid I failed. But, the answer is always correct if you go for the dot product of F \vec{F} and S \vec{S} directly. So, I would suggest you to do the same.

Ashish Menon - 4 years, 11 months ago

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Yes exactly i too failed. That's why i asked the doubt.

Jus Jaisinghani - 4 years, 11 months ago

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@Jus Jaisinghani Hehe, wierd stuff right? I lost 5 marks in exam when i tried somwthing "fancy" for the first time :P

Ashish Menon - 4 years, 11 months ago

@Jus Jaisinghani Here is one relevant problem for this topic I posted.

Ashish Menon - 4 years, 11 months ago

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@Ashish Menon hey i got that one correct

Jus Jaisinghani - 4 years, 11 months ago

I did the same and got correct answer. s(vector) = (8,-12,-28)

A Former Brilliant Member - 4 years, 11 months ago

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ya bro i got my silly mistake :) and then got it correct

Jus Jaisinghani - 4 years, 11 months ago

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