In the figure above, ∠ D A B = 1 1 1 ∘ . Find the value of x .
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
3rd line of the calculation is like written by typical mathematics professor at uni 😂 I still like it tho
Using simultaneous equations:
Let ∠ D A C measure y degrees. Then ∠ B C A also measures y degrees (alternate interior angles).
By angle addition, y + 4 x = 1 1 1 . Using same-side interior angles, ∠ D C B must measure 90 degrees, so x + y = 9 0 as well.
Solving the second equation for y, y = 9 0 − x . Substituting into the first equation, 9 0 − x + 4 x = 1 1 1 . Solving yields the answer x = 7.
Using expressions:
The measure of ∠ D A C can be rewritten as 111 - 4x. Then the three angles inside the triangle measure (111-4x), 90, and x. Writing an equation using the fact that the angles in a triangle sum to 180:
111 - 4x + 90 + x = 180
Again, solving yields the answer x = 7.
Challenging question
A challenging question.
I think the parallel lines are immaterial. Without this information we can solve the problem
Log in to reply
They are! However, sometimes having extra information makes the problem harder to solve. You have to know what is important and what isn't.
Log in to reply
I think if you change angle B given instead , it will be more sophisticated ...
Log in to reply
@Alfa Claresta – I am not seeking to make extra calculations; the challenge in this problem is knowing what calculations to do.
∠ D A B = 4 x + y and in the ADC right-angled triangle we've got x + y + 9 0 = 1 8 0 => 4 x + y − x − y = 1 1 1 − 9 0 => 3 x = 2 1 => x = 7
Draw a line || to CD such that it meets BC at E. Angle DCA = Angle CAE = x°(alternate interior angles) Then Angle EAB = 4x°-x°=3x° Angle DAE = 180°-90°=90 Angle DAE + Angle EAB = 111° 90° + 3x° = 111 Therefore , x=7°
in Triangle ADC, ADC=90, DAC+ACD=90, 111-4x+x=90, 111-3x=90, 3x=21, x=7
Problem Loading...
Note Loading...
Set Loading...
∠ D A C = 1 1 1 ∘ − 4 x ∘
x ∘ + 9 0 ∘ + ( 1 1 1 − 4 x ) ∘ = 1 8 0 ∘
The rest is left as an exercise for the student.