What will happen to the gas? - 2

Chemistry Level 2

As the temperature is increased from $20^\circ$ to $40^\circ$ , the average kinetic energy of neon atoms changes by a factor:

Note: Temperature in Kelvin scale = Temperature in Celsius scale + $273$ (For this problem)

2

\sqrt(\dfrac{313}{293})

\dfrac{1}{2}

\dfrac{313}{293}

1 solution

Skanda Prasad
Oct 13, 2016

$\dfrac{KE_1}{KE_2}$ = $\dfrac{T_1}{T_2}$ Where $KE_1$ and $KE_2$ are initial and final kinetic energies of the gas. Also $T_1$ and $T_2$ are respectively initial and final temperatures of the gas.

$KE_2$ $=$ $\dfrac{40+273}{20+273}\times$ $KE_1$

$=$ $\dfrac{313}{293}$

@Skanda Prasad Shouldn't KE1 proportional to T1 ..?

Saraswati Sharma - 4 years, 8 months ago

Umm...I don't think so...what I learnt was that KE and T are indirectly proportional...I'll try to confirm on this...

Skanda Prasad - 4 years, 8 months ago

@Skanda Prasad In KTG , K.E. =3/2 kT remember ? From here K.E. is directly prop. to Temperature.

Saraswati Sharma - 4 years, 8 months ago

@Saraswati Sharma – Oh, yeah...then it will be $\dfrac{293}{313}$ , I believe?

Skanda Prasad - 4 years, 8 months ago

@Saraswati Sharma – oops, yeah, u r right I'll change it straight away

Skanda Prasad - 4 years, 7 months ago

What will happen to the gas? - 2

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