What's in a squared?

Algebra Level 1

True or False?

If x , y x, y are real numbers such that x 2 = y 2 x^2 = y^2 , then

x = y . x = y.

Sometimes true, sometimes false Always false Always true

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

9 solutions

Ben Habeahan
Aug 26, 2015

Consider 3 case:

(i) if x = y = 0 , x=y=0, we can have x 2 = y 2 = 0. x^2=y^2=0. It means statement x 2 = y 2 x = y x^2=y^2 \implies x=y always true.

(ii) if x < 0 , y > 0 x<0,y>0 ( or x > 0 , y < 0 x>0,y<0 ), we can have x 2 > 0 , y 2 > 0. x^2>0,y^2>0. It means statement x 2 = y 2 x = y x^2=y^2 \implies x=y always false, because the signs x , y x,y are opposite.

(iii) if x < 0 , y < 0 x<0,y<0 ( or x > 0 , y > 0 x>0, y>0 ), we can have x 2 > 0 , y 2 > 0. x^2>0,y^2>0. It means statement x 2 = y 2 x = y x^2=y^2 \implies x=y always true, because the sign x , y x,y are same.

From (i),(ii) and (iii) s o m e t i m e s t r u e , s o m e t i m e s f a l s e \boxed{sometimes true, sometimes false}

If x 2 = a x x^2=a \Rightarrow x could be positive or negative.

If y 2 = a ( x 2 = y 2 ) y y^2=a (x^2=y^2) \Rightarrow y could be positive or negative.

Therefore, it is true and false.

x 2 x^2 = y 2 y^2 means x 2 x^2 - y 2 y^2 = 0 so either x-y=0 (x=y) or x+y=0 (x=-y) so x and y are not always equal

Brendix Emata
Aug 31, 2015
  1. x^2 =y^2 ; 2. x^2-y^2 = 0; 3. Factor: (x+y) (x-y) =0
  2. So, its is either x+y = o or x-y =o 5. Finally It is either x=-y or x=y.
Clarence Millares
Aug 31, 2015

the square root of x and y could be either positive or negative...

for example: 4=4

both x^2 and y^2 is 4

4 could have a square root of +2 and -2

if that's the case, +2 could be x and -2 could be y, which in that case, x=y won't be true

Khizar Rehman
Aug 24, 2015

square root results in both positive and negative signs......... so not true always ....

Vijay Kumar
Aug 31, 2015

in general , if x^2=y^2 . then x\quad =\quad \pm \sqrt { { y }^{ 2 } } therefore ,, x\quad =\quad \pm y

Hadia Qadir
Aug 31, 2015

Sometimes true, sometimes false. √x²=√y², x=y, or, x=(-y), or, (-x)=y.

Dev Sharma
Aug 20, 2015

Counter example.

x = 2 and y = -2

So why not "Always false"?

Calvin Lin Staff - 5 years, 9 months ago

Log in to reply

In case of x = 2 and y = 2, its true!!

Dev Sharma - 5 years, 9 months ago

Log in to reply

Right, so that needs to be stated in your solution. Almost all of us are not mind readers, and can only deduce from what you have written.

Calvin Lin Staff - 5 years, 9 months ago

Log in to reply

@Calvin Lin Sorry. I would take care of it.

Dev Sharma - 5 years, 9 months ago

Log in to reply

@Dev Sharma I think the answer should be always false. Why? Well the question asks: True or false? and then makes a statement - an incorrect statement. It is indeed false that from x^2 = y^2, one cannot deduce x=y. It is possible with some other inputs, but using solely x^2 = y^2, that is impossible to deduce. So I would say that such a deduction is always logically incorrect.

The point is that I understood the question to be: "Is the following deduction always true, always false, or sometimes true and sometimes false?" and such a deduction is always false. Right?

Alija Bevrnja - 5 years, 9 months ago

Log in to reply

@Alija Bevrnja @Calvin Lin , this reasoning is correct. Please check

Agnishom Chattopadhyay - 5 years, 8 months ago

Log in to reply

@Agnishom Chattopadhyay The difference is the statement at the start, namely "If x and y are real numbers", which means that they are already fixed values. IE "If 2 and 2 are real numbers such that 2 2 = 2 2 2^2 = 2^2 , then 2 = 2 2 = 2 " is a true statement.

If the statement was x 2 = y 2 x = y x^2 = y^2 \Rightarrow x = y , where these are variables, then this is always false. In terms of variables, we can only say that x = ± y x = \pm y .

Calvin Lin Staff - 5 years, 8 months ago

Log in to reply

@Calvin Lin Okay, but how would an implication be stated using words. As far as I know, wording IF...THEN has the meaning of implication.

I do not see why the sentence "If x and y are real numbers..." has to imply fixed values. One has to say that they are real numbers, so that we know the domain of the problem...like writing x , y R x,y \in R .

What I am saying is that the full problem can be restated as: x , y R , x 2 = y 2 x = y x,y \in R, x^2 = y^2 \Rightarrow x=y If not, then I ask the question, how to rephrase my mathematical statement (which can either be true or false - and is false in this case) into words.

Alija Bevrnja - 5 years, 8 months ago

I agree. Actually, a statement stated in general is False even if there is just one counterexample. I trust that logic here should be bivalent because the notion of 'not always' is ambiguous.

How about I say that x = 4x is sometimes true, because there is one solution?

Agnishom Chattopadhyay - 5 years, 8 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...