Which Four Integers?

4 consecutive integers can be written as $odd\cdot even \cdot odd\cdot even =a\cdot 2p \cdot b \cdot 2m=4abpm$ for all odd integers $a$ , $b$ , $p$ and $m$

In every sequence of four consecutive integers, there's a multiple of 4.

In fact, the product of 4 consecutive integers is divisible by 24. More generally, the product of n consecutive integers is divisible by n!.

4 consectitive integers = Odd × Even × Odd × Even (or) Evsn × Odd × Even × Odd. Now two evens always appear in this. And these even nhmbers are multiples of 2 each. And 2×2 = 4 So, these 2 numbers themselves multiply to form a number divisible by 4 and if we multiply 2 odd numbers to this product, it woukd still remain a number divisible by 4.