Why don't people understand this basic?

Algebra Level 2

1 4 = . . . \sqrt{-1} \sqrt{-4} = ...

2 -2 -2i 2i Cannot be solved

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2 solutions

Rohit Udaiwal
Sep 30, 2015

ι × 2 ι = 2 ι 2 \iota×2\iota =2\iota^{2} As ι 2 = 1 \iota^{2}=-1 the value of it becomes 2 -2 .

Great job, as most other people don't understand that x 2 ± x \sqrt{x^2}\neq \pm x , while the truth is x 2 = x \sqrt{x^2}=|x| .

Gian Sanjaya - 5 years, 8 months ago

I have answered -2 , too, but actually, the right answer is 2 or -2. Why?

1.- 1 4 = \sqrt{-1}\sqrt{-4}= i(2i) = -2

2.- 1 4 = \sqrt{-1}\sqrt{-4}= ( 1 ) ( 4 ) 2 \sqrt[2]{(-1)\cdot (-4)} = 4 2 \sqrt[2]{4} = 2

Furthemore in 1, I can see another little mistake...

Guillermo Templado - 5 years, 8 months ago

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second one is actually the one with mistake.

( a ) ( b ) = ( a b ) \sqrt(a)\sqrt(b)=\sqrt(ab) DOES NOT APPLY for a , b ( , 0 ) a, b \in (-\infty, 0) .

Gian Sanjaya - 5 years, 8 months ago

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let's suposse you are right, then why you choose i for (-1)^(1/2)? Can't you choose -i?

Guillermo Templado - 5 years, 8 months ago

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@Guillermo Templado it is a definition. Plus, even if you choose -i, as long as you're consistent with using -i, you will still get -2. SO after all, inconsistence is the one that leads to multiple answers (while there are only 1 right answer).

Gian Sanjaya - 5 years, 8 months ago

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@Gian Sanjaya what is the definition, please?

Guillermo Templado - 5 years, 8 months ago
Mahdi Raza
Jun 2, 2020

\[\begin{align} \sqrt{-1} \cdot \sqrt{-4} &= i\sqrt{1} \cdot i\sqrt{4} \\ &= 1i \cdot 2i \\ &= 2i^2 \\ &= 2(-1) \\ &= \boxed{-2}

\end{align}\]

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