Why is binary so complicated?
The answer to this question is found by decrypting this binary code.
0010101001001110100010100 10000011001010110011 101000010101110
Hint:
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The number 5. That is not the answer but it will help you decrypt.
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01011 = K
The answer is 18.
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1 solution
Yay, people managed to decrypt the code. How long did it take?
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Dude, was this inspired by my code-breaking problem? :P
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A bit. I hade a question like that a bit back but the code was much longer.
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@Sharky Kesa – Okay, I see. ;)
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@Finn Hulse – Have you managed to solve that one? It's the same coding exactly.
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@Sharky Kesa – No, haven't had a chance. Right now I'm doing JOMO! It's so awesome! :D
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@Finn Hulse – Same here.
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@Sharky Kesa – Dude, #2 is literally impossible! :O
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@Finn Hulse – I know!!! I hate combinatorics. I may be level 5 but I still hate it. It a genetic thing, says mum.
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@Sharky Kesa – Wait is your mum a mathematician? But yeah, I'm loving the proof-based ones!
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@Finn Hulse – No, but she is good at math. During high school she hated combinatorics.
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@Sharky Kesa – Haha, yeah. In America, a person's lucky just to even hear that word. Honestly, the curriculum here sucks horribly. Also, have you proved #1 on JOMO for short answer? It's my favorite. :D
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@Finn Hulse – ope, was working on it though. Created a couple of tables to help me. Digit sums, total, etc. Also working on #2 for long answer.
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@Sharky Kesa – Woah dude. I assure you, there's a really beautiful, 1 paragraph proof that I found.
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@Finn Hulse – Finished #2 on long answer.
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@Sharky Kesa – I though that one was pretty easy. Did you use inscribed tetrahedrons and stuff like that?
@Finn Hulse – Could you by any chance share this proof?
Well, actually it yielded "FIGHT PLUS TEN"... ._.
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Sorry, edited it.
HAHAHAHAHAHAHAHAHA It's one thing to get in a fight, it's a whole other to get in a fight with 10 or more people. That just sucks. :D
Did it? Well, I, too got the same! I even entered that into Google Search if it was some famous thing.:P I felt that I would have made a mistake decoding and so felt it would be E.
Break down the code into groups of five, turn each into decimal from binary, and find the alphabet at that place.
For e.g. ( 0 1 0 1 1 ) 2 = ( 1 1 ) 1 0 -> the alphabet 'K' as it appears in the eleventh place among the alphabets.
Doing this, yields "EIGHT PLUS TEN" which of course is 1 8 and we are done!