Why my calculator? Why?

There are various reasons why this is wrong, though the calculator shows that it is correct. I will give you a simple introduction about this problem: it is not true, because it is a violation of Fermat's Last Theorem. This is known as a "Fermat near miss."

A calculator will tell you that two sides are equal, but there are digits of the numbers that are not equal.

---

For the people who don't know what is the Fermat's Last Theorem, here is a simple and quick idea:

The Fermat's Last Theorem states that there is no integer that $n$ can hold when $n>2$ in the following equation:

$\large \color{#EC7300} x^n + y^n = z^n$

Getting the link to the question; the question states that:

$\large \color{#3D99F6} 1782^{12} + 1841^{12} = 1922^{12}$

Therefore this can't be true becuse it is violating the Fermat's Last Theorem so the answer to this question is $\large \color{#20A900} \text {No}$

---

You can checkout the wiki on Fermat's Last Theorem

The last digit of 1782^12 must be an even number. The last digit of 1841^12 must be 1. The last digit of 1922^12 must be an even number.