Let
P
be an interior point of triangle
A
B
C
.
Let
Q
and
R
be the reflections of
P
in
A
B
and
A
C
, respectively.
If Q A R is a straight line, find ∠ B A C in degrees.
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did the same
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Let the angle made by P A with A B and A C be α and β respectively.
Now, the fact that angle of incidence and angle of reflection are same shows that the following hold : ∠ P A Q = 2 α ∠ P A R = 2 β
As Q A R is a straight line, ∠ P A Q + ∠ P A R = 1 8 0 ∘ ⟹ ∠ A = α + β = 9 0 ∘
Can you please explain how you get ∠ P A Q = 2 α ? Thanks.
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This follows from the fact that angle of incidence is equal to the angle of reflection.
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It wold be better if this is mentioned in your solution.
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@Niranjan Khanderia – I've now added that justification.
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@A Former Brilliant Member – Thank you. It adds to the quality of solution.
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