Why this type of triangle has more properties?

Geometry Level 1

Let P P be an interior point of triangle A B C ABC .
Let Q Q and R R be the reflections of P P in A B AB and A C AC , respectively.

If Q A R QAR is a straight line, find B A C \angle BAC in degrees.

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The answer is 90.

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3 solutions

2 α + 2 β = 18 0 A = α + β = 9 0 2\alpha+ 2\beta = 180^\circ \implies \angle A = \alpha + \beta = 90^\circ

SOLUTION WITHOUT WORDS

did the same

Steven Linnell - 4 years, 5 months ago

Did the same

Aarush Priyankaj - 2 years, 9 months ago

Let the angle made by P A PA with A B AB and A C AC be α \alpha and β \beta respectively.

Now, the fact that angle of incidence and angle of reflection are same shows that the following hold : P A Q = 2 α P A R = 2 β \angle PAQ = 2\alpha \\ \angle PAR = 2\beta

As Q A R QAR is a straight line, P A Q + P A R = 18 0 A = α + β = 9 0 \angle PAQ + \angle PAR = 180^\circ \implies \angle A = \alpha + \beta = 90^\circ

Can you please explain how you get P A Q = 2 α \angle \ PAQ=2\alpha ? Thanks.

Niranjan Khanderia - 4 years, 6 months ago

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This follows from the fact that angle of incidence is equal to the angle of reflection.

A Former Brilliant Member - 4 years, 6 months ago

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It wold be better if this is mentioned in your solution.

Niranjan Khanderia - 4 years, 6 months ago

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@Niranjan Khanderia I've now added that justification.

A Former Brilliant Member - 4 years, 6 months ago

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@A Former Brilliant Member Thank you. It adds to the quality of solution.

Niranjan Khanderia - 4 years, 6 months ago

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