Because $\Large\underbrace{a+a+ \ldots+a}_{n \text{ number of }a\text{'s}} = a\times n$ , we have

$5^{55} + 5^{55} + 5^{55} + 5^{55} + 5^{55} = 5^{55} \times 5 = 5^{55} \times 5^1$

By the Rules of Exponents , we get $5^{55} \times 5^1 = 5^{55 + 1} = 5^{56}$ .

So the answer is 56.

the Solution is

$a+a = 2 (a)$

$5^{55}+5^{55}+5^{55}+5^{55}+5^{55}=(5) 5^{55}= \boxed{5^{56}}$

$5^{55} + 5^{55} + 5^{55} + 5^{55} + 5^{55} = 5(5^{55})$ $= 5^{1} * 5^{55} = 5 ^{1 +55} = \boxed{5^{56}}$

You are just adding $5^{55}$ 5 times, meaning that it's just $5^{56}$ .

Simply 5^55(1+1+1+1+1)

5^55(5)

5^(55+1)

5^56

a^m×a^n=a^(m+n)

=5^55 ( 1 + 1+1+1+1) =5^55 (5) =5^55 * 5^1 =5^(55+1) =5^56 = required solution .

i use this method

5^1+5^1+5^1+5^1+5^1=5^2

5^2+5^2+5^2+5^2+5^2=5^3

5^3+5^3+5^3+5^3+5^3=5^4

5^4+5^4+5^4+5^4+5^4=5^5 . . .

5^n+5^n+5^n+5^n+5^n=5^n+1

so 5^55+5^55+5^55+5^55+5^55=5^55+1=5^56

5^55+5^55+5^55+5^55+5^55

=5*5^55

=5^1*5^55=5^56

Just take 5^55 common from all terms. It becomes 5^55 (1+1+1+1)=5^55×5^1=5^56

The Answer is write. In here, where is the problem?

$5^{55} + 5^{55} +5^{55} +5^{55} +5^{55}$

$= 5 \times 5^{55}$

$= 5^1 \times 5^{55}$

$= 5^{1+55}$

$=5^{56}$

there are 5 5^55s which gives 5^56

It is a very simple problem 5^55 added by itself 5 times is equivalent to (5)5^55 which equals 5^56. I don't understand how only 53% of people got this right

We know that $\Large\underbrace{a+a+ \ldots+a}_{n \text{ number of }a\text{'s}} = a\times n$ , so we have,

$5^{55} + 5^{55} + 5^{55} + 5^{55} + 5^{55} = 5^{55} \times 5 = 5^{55} \times 5^1$

By following Rules Of Exponents , we get $5^{55} \times 5^1 = 5^{55 + 1} = 5^{56}$

So the answer is $5^{56}$ .

Laws of exponents.

The above equation is equivalent to 5 × 5^55, or 5^56.

If you are calaulating 2+2, 2+2=2 times 2= 2^2. Also, if you are calaulating 3^2+3^2+3^2=3(3^2)=3^3. On the same principle, 5^55+5^55+5^55+5^55+5^55=5(5^55)=5^56.

We have 5 to the power of 55 added together 5 times, therefore it would be 5 times 5 to the power of 55, which would be 5 to the power of 56.

$5^{55}+5^{55}+5^{55}+5^{55}+5^{55}=5^{55}(1+1+1+1+1)=5^{55} \times 5=\boxed{\large{5^{56}}}$

This Q. is based on a^m.b^n=a(^m+n) the Q. is 5^55+5^55+.....5^55=? and the ans is 5^55 ×5^1=5^55+1=5^56

5^55+5^55...5 times= 5^1*5^55=5^56

5^55+5^55+5^55+5^55+5^55 =5*5^55 =5^(1+55) =5^56

The answer is 5^56 because in the question 5^55 comes 5 times. So, we can simply do 5 * 5^55 and get 5^56 as the result.

Since this can be factorised to 5^55(1+1+1+1+1), which equals 5^55 multiplied by 5, by the laws of indecies it is equal to 5^56

5^55 (1+1+1+1+1) =5^55 (5) =5^56