For a real x satisfying x 2 − 2 x + 6 6 x 2 − 5 x − 3 ≤ 4 ,
the least and the highest values of 4 x 2 are A and B respectively.
Find the value of A − B .
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Nice solution.
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Thanks,sir
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Before disputing any problem, you first need to be 100% sure. Otherwise none should report the problem. And must look at the solution (if given) before going to report any problem. @brilliant
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@Sandeep Bhardwaj – And you should have seen my face when at first 8 1 was marked wrong.
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@Satvik Golechha – Hahaha.Easy problem LOL
@Satvik Golechha – waiting for you march newsletter.
@Sandeep Bhardwaj – Yes i agree.
Same way as I did.
I did 81 - 36 first and later realised while solving again that it's minimum value will be zero! Nice solution !😀
the value of x after solving the inequalities is [-4.5,3] but after squaring the value of x^2 is [0,20.25] hence the least A=0 and highest B=4x20.25=81 and 0-81=-81 hence the solution
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I think,This problem has been reported by multiple members because they are subtracting LEAST from the HIGHEST and getting +81 instead of -81
x 2 − 2 x + 6 = ( x − 1 ) 2 + 5 is always +ve so multiply by it both side without affecting inequality sign.
6 x 2 − 5 x − 3 ≤ 4 x 2 − 8 x + 2 4 ⇒ 2 x 2 + 3 x − 2 7 ≤ 0 ⇒ ( 2 x + 9 ) ( x − 3 ) ≤ 0 ⇒ x ∈ [ 2 − 9 , 3 ] ⇒ x 2 ∈ [ 0 , 4 8 1 ] ⇒ A − B = 4 ( 0 − 4 8 1 ) = − 8 1