Yeah a bit of logic...
Electricity and Magnetism
Level
pending
Ten identical cells each of emf 2 volt and internal resistance 0.5ohm are in series with some cells improperly connected. The resistance in the circuit is 11ohm and the current flowing through the circuit is 1amp. How many cells are wrongly connected?
1
3
2
5
4
0
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1 solution
let 'n' number of cells are connected improperly. therefore number of cells active in the circuit (10 - 2n). total emf = 2 (10 - 2n). current = (2 (10 - 2n))/total resistane.
current = (2*(10 - 2n))/16. Now we have current in the circuit = 1 amp
substituting the value of current we get n = 1. So one cell is connected improperly.