You don't need implicit differentiation, part II

Calculus Level 4

If y = x x x . . . y = \displaystyle \sqrt{\dfrac{x}{\sqrt{\dfrac{x}{\sqrt{\dfrac{x}{\sqrt{}...}}}}}} , find d y d x x = 8 \left. \dfrac{dy}{dx} \right|_{x= -8}

4 3 \dfrac{4}{3} 1 12 \dfrac{1}{12} 4 3 - \dfrac{4}{3} 1 12 - \dfrac{1}{12} The derivative does not exist

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1 solution

There is no real value of y y such that x = 8 x=-8 , because x \sqrt{x} is not defined as a real number for x < 0 x<0

Correct. But do you want to explain why?

Hobart Pao - 5 years, 2 months ago

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Is it right the explanation?

Hjalmar Orellana Soto - 5 years, 2 months ago

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It looks good now. (+1). Thanks!

Hobart Pao - 5 years, 2 months ago

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@Hobart Pao Thanks you for giving me the advice

Hjalmar Orellana Soto - 5 years, 2 months ago

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@Hjalmar Orellana Soto np lol it was a miniscule thing

Hobart Pao - 5 years, 2 months ago

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