Alphys Won't Help You This Time!
Two trains, Train A , and Train B , simultaneously depart Station A and Station B . Station A, and Station B are 2 5 2 . 5 miles apart from each other. Train A is moving at 1 2 4 . 7 m p h towards Station B, and Train B is moving at 2 5 3 . 5 m p h towards Station A.
If both trains departed at 1 0 : 0 0 AM and it is now 1 0 : 0 8 , how much longer until both trains pass each other? Round to three decimal places and answer in minutes.
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The answer is 32.058.
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3 solutions
üzgünüm ama cevabı yazamadım çünkü bunu kodla nasıl yapacağımı bilmiyorum
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Bunun için kod kullanmanız gerekmez; bunu çözmek için sadece temel kinematik kullanın
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I don't know much about the code
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@Ömer Ertürk – All good; why don't you try out the python course here on Brilliant?
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@Anonymous1 Assassin – I think there are 2 reasons ;
1st reason: I don't like coding
2nd reason : I spend a lot of time on this site so I cannot study my classes.
Let Train A's distance be x miles, and Train B's be 2 5 2 . 5 − x miles to their meeting point. If 8 minutes (or 1 5 2 hours) have elapsed, then the remaining time to encounter, call it t hours, can be calculated per following system of equations:
t + 2 / 1 5 x = 1 2 4 . 7 (i)
t + 2 / 1 5 2 5 2 . 5 − x = 2 5 3 . 5 (ii)
Solving (i) for x and substituting into (ii) gives us:
t + 2 / 1 5 2 5 2 . 5 − 1 2 4 . 7 ( t + 2 / 1 5 ) = 2 5 3 . 5 ⇒ t = 5 6 7 3 0 3 0 3 1 1 ⋅ 6 0 = 3 2 . 0 5 8 minutes.
i solved it with a python program, for the file: https://www.dropbox.com/s/phh0yuiqjqran8t/AlphysWillnotHelpYouThisTimeProblem.py?dl=0
I couldn't be bothered to solve using code so I just did it the old-fashioned way: