Zero Exponent Expose
Solve this mathematical equation:
1 + d 0 x 0 ( 2 c x ) 0
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1 solution
That's right. No matter the variable or number that is raised by zero power, it will give also a value of one.
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so 0^0 is 1? what i know is it's indeterminate. if it is 1, can u pls show me a proof? thanks :)
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0^0 is 1 ... this is true and proof is given by calculus . i don't know much calculus ..but u can search for it -
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@Nihar Mahajan – Oh, maybe I forget that one condition that it is except for zero because 0^0 is not always one.....thanks for clarification
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@Merzel Mark Guilaran – no friend ... 0^0 is 1 only
@Nihar Mahajan – really? how about this
x 0 = x 1 − 1 = x x = 1 S o i f x = 0 0 0 = 0 1 − 1 = 0 0 = i n d e t e r m i n a t e
So why is it 1?
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@Justin Tuazon – In some cases, if x is represented by any real numbers except for zero, for sure the value of it is 1. If we adhere that 0^0 is 1, then we do not obey the basic algebra law that 0/0= undefine or indeterminate.
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@Merzel Mark Guilaran – so 0^0 is 1 or indeterminate? im really curious on this topic lol
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@Justin Tuazon – http://www.askamathematician.com/2010/12/q-what-does-00-zero-raised-to-the-zeroth-power-equal-why-do-mathematicians-and-high-school-teachers-disagree/
@Justin Tuazon – visit the url given below and u will get a calculus proof there :)
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@Nihar Mahajan – i consulted a group and they said it's indeterminate, it's only a limit so it doesn't actually equal to 1. so for me it's indeterminate but thanks anyway :)
@Justin Tuazon – Okey. To stop this argumentation, I will make a mathematical proof for it.
( 2 c x ) 0 = 1 , x 0 = 1 , d 0 = 1 . E x p . = 1 + 1 1 1 = 1 + 1 1 = 2 1 = 0 . 5
I am adding this note :-We assume non of the c, d, or x is equal to zero. If any of them is zero, there is no solution.