Zero power Itself

Algebra Level 2

We all know the exponential identity,

a n = 1 a n a 0 = 1 a^{-n} = \frac{1}{a^{n}} \\ a^{0} = 1

So, what is the value of 0 0 0^0 using any of above identities?

Undefined -1 0 1

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1 solution

Viki Zeta
Jun 27, 2016

On finding how they got a 0 = 1 a^0 = 1

a 0 = a n n = a n × a n = a n a n a^0 = a^{n-n} = a^{n} \times a^{-n} = \frac{a^n}{a^n}

So, now on setting any value for n > 0 n > 0 , you get

0 0 = 0 n 0 n ; n > 0 = > 0 0 = 0 0 We all know that ’0’ divided by ’0’ is undetermined or undefined, so 0 0 is undefined too. 0^0 = \frac{0^n}{0^n} ; n > 0 \\ => 0^0 = \frac{0}{0} \\ \text{We all know that '0' divided by '0' is undetermined or undefined, so }0^0 \text{ is undefined too.}

Wrong. 0 0 \dfrac{0}{0} is not undefined, it is indeterminate. These two terms have completely different meanings

Hung Woei Neoh - 4 years, 11 months ago

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I'll give a simple answer for which 0 0 \frac{0}{0} is undefined as-well-as indeterminate.

0 0 = 0 × 1 0 = 0 u n d e f i n e d = u n d e f i n e d , 0 \frac{0}{0} = 0 \times \frac{1}{0} = 0 * undefined = undefined, 0

Viki Zeta - 4 years, 11 months ago

0÷0 is undefined. Get a dictionary.

Viki Zeta - 4 years, 11 months ago

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I did my research before I reported this question

Indeterminate: An expression which has a value, but whose value cannot be determined exactly. For example, we know that

a × 0 = 0 a \times 0 = 0

a a can take any value, therefore 0 0 \dfrac{0}{0} can actually take any value, and therefore is indeterminate

Undefined: An expression which cannot be defined or has no meaning at all. For example, consider

a × 0 = b a \times 0 = b

We know b b cannot be non-zero. Therefore, b 0 \dfrac{b}{0} , where b 0 b\neq 0 is undefined

Hung Woei Neoh - 4 years, 11 months ago

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Let me come to your point of view,

0 0 = 0 0 = 1 0 0 0^0 = 0^{-0} = \frac{1}{0^{0}} , according to your statement, 0 0 0^0 is indeterminate, let it be, but 1 0 \frac{1}{0} is not defined, so the answer is undefined.

Viki Zeta - 4 years, 11 months ago

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@Viki Zeta Here, you are assuming that 1 0 0 = 1 0 \dfrac{1}{0^0} = \dfrac{1}{0} , which means you are saying that 0 0 = 0 0^0 = 0

Hung Woei Neoh - 4 years, 11 months ago

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@Hung Woei Neoh No I mean any value maybe for 0 0 0^0 , Even 0, but we know 1 0 \frac{1}{0} is undefined, so the answer is undefined.

Viki Zeta - 4 years, 11 months ago

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@Viki Zeta So what happens if 0 0 0^0 is not zero? Your logic is flawed

Therefore, as long as we cannot determine the exact value , we say that it is indeterminate

Hung Woei Neoh - 4 years, 11 months ago

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