We all know the exponential identity,
a − n = a n 1 a 0 = 1
So, what is the value of 0 0 using any of above identities?
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Wrong. 0 0 is not undefined, it is indeterminate. These two terms have completely different meanings
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I'll give a simple answer for which 0 0 is undefined as-well-as indeterminate.
0 0 = 0 × 0 1 = 0 ∗ u n d e f i n e d = u n d e f i n e d , 0
0÷0 is undefined. Get a dictionary.
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I did my research before I reported this question
Indeterminate: An expression which has a value, but whose value cannot be determined exactly. For example, we know that
a × 0 = 0
a can take any value, therefore 0 0 can actually take any value, and therefore is indeterminate
Undefined: An expression which cannot be defined or has no meaning at all. For example, consider
a × 0 = b
We know b cannot be non-zero. Therefore, 0 b , where b = 0 is undefined
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Let me come to your point of view,
0 0 = 0 − 0 = 0 0 1 , according to your statement, 0 0 is indeterminate, let it be, but 0 1 is not defined, so the answer is undefined.
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@Viki Zeta – Here, you are assuming that 0 0 1 = 0 1 , which means you are saying that 0 0 = 0
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@Hung Woei Neoh – No I mean any value maybe for 0 0 , Even 0, but we know 0 1 is undefined, so the answer is undefined.
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@Viki Zeta – So what happens if 0 0 is not zero? Your logic is flawed
Therefore, as long as we cannot determine the exact value , we say that it is indeterminate
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On finding how they got a 0 = 1
a 0 = a n − n = a n × a − n = a n a n
So, now on setting any value for n > 0 , you get
0 0 = 0 n 0 n ; n > 0 = > 0 0 = 0 0 We all know that ’0’ divided by ’0’ is undetermined or undefined, so 0 0 is undefined too.